f^2-10f+19=0

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Solution for f^2-10f+19=0 equation:


Simplifying
f2 + -10f + 19 = 0

Reorder the terms:
19 + -10f + f2 = 0

Solving
19 + -10f + f2 = 0

Solving for variable 'f'.

Begin completing the square.

Move the constant term to the right:

Add '-19' to each side of the equation.
19 + -10f + -19 + f2 = 0 + -19

Reorder the terms:
19 + -19 + -10f + f2 = 0 + -19

Combine like terms: 19 + -19 = 0
0 + -10f + f2 = 0 + -19
-10f + f2 = 0 + -19

Combine like terms: 0 + -19 = -19
-10f + f2 = -19

The f term is -10f.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10f + 25 + f2 = -19 + 25

Reorder the terms:
25 + -10f + f2 = -19 + 25

Combine like terms: -19 + 25 = 6
25 + -10f + f2 = 6

Factor a perfect square on the left side:
(f + -5)(f + -5) = 6

Calculate the square root of the right side: 2.449489743

Break this problem into two subproblems by setting 
(f + -5) equal to 2.449489743 and -2.449489743.

Subproblem 1

f + -5 = 2.449489743 Simplifying f + -5 = 2.449489743 Reorder the terms: -5 + f = 2.449489743 Solving -5 + f = 2.449489743 Solving for variable 'f'. Move all terms containing f to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + f = 2.449489743 + 5 Combine like terms: -5 + 5 = 0 0 + f = 2.449489743 + 5 f = 2.449489743 + 5 Combine like terms: 2.449489743 + 5 = 7.449489743 f = 7.449489743 Simplifying f = 7.449489743

Subproblem 2

f + -5 = -2.449489743 Simplifying f + -5 = -2.449489743 Reorder the terms: -5 + f = -2.449489743 Solving -5 + f = -2.449489743 Solving for variable 'f'. Move all terms containing f to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + f = -2.449489743 + 5 Combine like terms: -5 + 5 = 0 0 + f = -2.449489743 + 5 f = -2.449489743 + 5 Combine like terms: -2.449489743 + 5 = 2.550510257 f = 2.550510257 Simplifying f = 2.550510257

Solution

The solution to the problem is based on the solutions from the subproblems. f = {7.449489743, 2.550510257}

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